#### Answer

$28$

#### Work Step by Step

$(a^m)^n=a^{mn}$
Thus $4^{\frac{5}{2}}-8^{\frac{2}{3}}=(2^2)^{\frac{5}{2}}-(2^3)^{\frac{2}{3}}=2^{2\cdot\frac{5}{2}}-2^{3\cdot\frac{2}{3}}=2^5-2^2=32-4=28$

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Published by
Pearson

ISBN 10:
0-13417-894-7

ISBN 13:
978-0-13417-894-3

$28$

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